Jawaban:
Penyelesaian :
[tex]\begin{gathered} \begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{c}\rm \underline \red{tinggi \: balok \: : } \\ \\ \sf{ volume = p \times l \times t } \: \\ \\ \sf{ 162 \: {m}^{3} = 6 \times 3 \times t } \\ \\ \sf{ 162 \: {m}^{3} = 18t } \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf{ \: t = \frac{162}{18} } \: \\ \\ \: \sf{t = 9 \: m} \\ \\ \: \: \: \: \: \: \: \: \: \sf{t = 9 \times 100} \\ \\ \: \: \: \: \: \: \: \: \underline{ \boxed{ \red{ \sf{ t = 900 \: cm}}}}\end{array}}}\end{gathered} \end{gathered} \end{gathered}[/tex]
[tex]diketahui \\ p = 6 \: m\\ l = 3 \: m\\ \\ volume \: balok = p \times l \times t \\ 162 \: {m}^{3} = 6 \: m\times 3 \: m \times t \\ 162 \: {m}^{3} = 18 \: {m}^{2} \times t \\ \frac{162 \: {m}^{3} }{18 \: {m}^{2} } = t \\ t = 9 \: m = 900 \: cm[/tex]
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